What is the sum from n=0 to infinity of ne^{-n/2} ?

The sum from n=0 to infinity of ne^{-n/2} is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=0 to infinity of ne^{-n/2}

n = 0 \sum \infty n e^{- \frac{n}{2}}

converges

Solution steps

n = 0 \sum \infty n e^{- \frac{n}{2}}

Apply Series Ratio Test:

converges

= converges

\int_{4}^{\infty} \frac{1}{x ^{2} - 1} d x

\frac{d}{d x} (e^{x} cosh (x))

x \to 0 - lim (\frac{x}{8 x ^{4} + 2 x})

x \to 3 - lim ((x - 2)^{3})

\frac{0.9}{0.1 s ^{2} + s + 0.9}

What is the sum from n=0 to infinity of ne^{-n/2} ?
The sum from n=0 to infinity of ne^{-n/2} is converges