What is the derivative of e^xcosh(x) ?

The derivative of e^xcosh(x) is e^xcosh(x)+sinh(x)e^x

What is the first derivative of e^xcosh(x) ?

The first derivative of e^xcosh(x) is e^xcosh(x)+sinh(x)e^x

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\frac{d}{d x} (e^{x} cosh (x))

e^{x} cosh (x) + sinh (x) e^{x}

Solution steps

\frac{d}{d x} (e^{x} cosh (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cosh (x)

= \frac{d}{d x} (e^{x}) cosh (x) + \frac{d}{d x} (cosh (x)) e^{x}

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cosh (x)) = sinh (x)

= e^{x} cosh (x) + sinh (x) e^{x}

x \to 0 - lim (\frac{x}{8 x ^{4} + 2 x})

x \to 3 - lim ((x - 2)^{3})

\frac{0.9}{0.1 s ^{2} + s + 0.9}

\int \frac{5 + x}{x} d x

\int csc^{2} (x) - 1 d x

What is the derivative of e^xcosh(x) ?
The derivative of e^xcosh(x) is e^xcosh(x)+sinh(x)e^x
What is the first derivative of e^xcosh(x) ?
The first derivative of e^xcosh(x) is e^xcosh(x)+sinh(x)e^x