What is the integral from 1 to infinity of 1/(x^1) ?

The integral from 1 to infinity of 1/(x^1) is diverges

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integral from 1 to infinity of 1/(x^1)

\int_{1}^{\infty} \frac{1}{x ^{1}} d x

diverges

Solution steps

\int_{1}^{\infty} \frac{1}{x ^{1}} d x

Compute the indefinite integral:

\int \frac{1}{x ^{1}} d x = ln ∣ x ∣ + C

Compute the boundaries:

\int_{1}^{\infty} \frac{1}{x ^{1}} d x =

diverges

= diverges

f (x) = (3 x^{3} - 2) (x + 1)

\frac{d}{d x} (8 x e^{x} - 8 e^{x})

y = 4 x - 3 x^{2}, (2, - 4)

n = 0 \sum \infty \frac{n ^{4}}{4 ^{n}}

f (x) = 2 x + 5

What is the integral from 1 to infinity of 1/(x^1) ?
The integral from 1 to infinity of 1/(x^1) is diverges