What is the integral of 1/(x^{1/5)} ?

The integral of 1/(x^{1/5)} is 5/4 x^{4/5}+C

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integral of 1/(x^{1/5)}

\int \frac{1}{x ^{\frac{1}{5}}} d x

\frac{5}{4} x^{\frac{4}{5}} + C

Solution steps

\int \frac{1}{x ^{\frac{1}{5}}} d x

Apply the Power Rule

: \frac{5}{4} x^{\frac{4}{5}}

= \frac{5}{4} x^{\frac{4}{5}}

Add a constant to the solution

= \frac{5}{4} x^{\frac{4}{5}} + C

\frac{d}{d x} (\frac{( sin ( x ) )}{x})

\frac{d}{d x} (9 tan (7 x))

\frac{4 e ^{(- s)}}{( s ^{2} + 4 s + 13 )}

\int \frac{1}{x ^{2} - 6 x - 13} d x

y^{^{'}} = 0.0017 y (1500 - y)

What is the integral of 1/(x^{1/5)} ?
The integral of 1/(x^{1/5)} is 5/4 x^{4/5}+C