What is the derivative of 20cos(2x) ?

The derivative of 20cos(2x) is -40sin(2x)

What is the first derivative of 20cos(2x) ?

The first derivative of 20cos(2x) is -40sin(2x)

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\frac{d}{d x} (20 cos (2 x))

- 40 sin (2 x)

Solution steps

\frac{d}{d x} (20 cos (2 x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 20 \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= 20 (- sin (2 x) \cdot 2)

Simplify

= - 40 sin (2 x)

\frac{d}{d x} (2 ln (3 - x))

\frac{d}{d x} (x^{1})

\int_{- 1}^{4} ∣ x ∣ d x

\frac{2 s + 6}{8 s ^{2} - 2 s - 3}

y = 2 x^{2}, y^{2} = \frac{1}{2} x

What is the derivative of 20cos(2x) ?
The derivative of 20cos(2x) is -40sin(2x)
What is the first derivative of 20cos(2x) ?
The first derivative of 20cos(2x) is -40sin(2x)