What is the derivative of (3xy+7^2) ?

The derivative of (3xy+7^2) is 6(3xy+7)(x(dy)/(dx)+y)

What is the first derivative of (3xy+7^2) ?

The first derivative of (3xy+7^2) is 6(3xy+7)(x(dy)/(dx)+y)

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\frac{d}{d x} ((3 x y + 7)^{2})

6 (3 x y + 7) (x \frac{d y}{d x} + y)

Solution steps

\frac{d}{d x} ((3 x y + 7)^{2})

Apply the chain rule:

2 (3 x y + 7) \frac{d}{d x} (3 x y + 7)

= 2 (3 x y + 7) \frac{d}{d x} (3 x y + 7)

\frac{d}{d x} (3 x y + 7) = 3 (x \frac{d y}{d x} + y)

= 2 (3 x y + 7) \cdot 3 (x \frac{d y}{d x} + y)

Simplify

= 6 (3 x y + 7) (x \frac{d y}{d x} + y)

\int x^{2} ln (x^{4}) d x

\frac{d}{d x} ((sin (x))^{4})

\frac{\partial}{\partial x} (y^{4} cos (3 x))

\int \frac{3 x ^{2} + 2}{( x ^{3} + 2 x + 3 ) ^{5}} d x

y^{^{'}} = \frac{x ^{2} + y ^{2}}{x \cdot y}

What is the derivative of (3xy+7^2) ?
The derivative of (3xy+7^2) is 6(3xy+7)(x(dy)/(dx)+y)
What is the first derivative of (3xy+7^2) ?
The first derivative of (3xy+7^2) is 6(3xy+7)(x(dy)/(dx)+y)