What is the sum from n=1 to infinity}((x)^{n-1 of)/x ?

The sum from n=1 to infinity}((x)^{n-1 of)/x is Interval of convergence is-1<x<1

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sum from n=1 to infinity}((x)^{n-1 of)/x

n = 1 \sum \infty \frac{( x ) ^{n - 1}}{x}

Interval of convergence is - 1 < x < 1

Solution steps

n = 1 \sum \infty \frac{x ^{n - 1}}{x}

Use the Ratio Test to compute the convergence interval

Interval of convergence is - 1 < x < 1

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What is the sum from n=1 to infinity}((x)^{n-1 of)/x ?
The sum from n=1 to infinity}((x)^{n-1 of)/x is Interval of convergence is-1<x<1