What is the integral from 1 to 49 of 1/(2x) ?

The integral from 1 to 49 of 1/(2x) is ln(7)

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integral from 1 to 49 of 1/(2x)

\int_{1}^{49} \frac{1}{2 x} d x

ln (7)

Decimal Notation

1.94591 \dots

Solution steps

\int_{1}^{49} \frac{1}{2 x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{1}^{49} \frac{1}{x} d x

Use the common integral:

\int \frac{1}{x} d x = ln (∣ x ∣)

= \frac{1}{2} [ln ∣ x ∣]_{1}^{49}

Compute the boundaries:

2 ln (7)

= \frac{1}{2} \cdot 2 ln (7)

Simplify

= ln (7)

\frac{d}{d x} (\frac{x ^{2}}{3})

t \cdot e^{- 5 t}

f (x) = 5 x + 4

x \to - 7 lim (\frac{1}{x ^{2} ( x + 7 )})

(81 - x^{2}) y^{^{'}} = 7 y

What is the integral from 1 to 49 of 1/(2x) ?
The integral from 1 to 49 of 1/(2x) is ln(7)