What is taylor 4x^{-1} ?

The answer to taylor 4x^{-1} is 4-4(x-1)+4(x-1)^2-4(x-1)^3+4(x-1)^4+\ldots

Popular >

taylor 4x^{-1}

taylor

4 x^{- 1}

4 - 4 (x - 1) + 4 (x - 1)^{2} - 4 (x - 1)^{3} + 4 (x - 1)^{4} + \dots

Solution steps

Apply the Taylor Formula

= 4 + \frac{\frac{d}{d x} ( 4 x ^{- 1} ) ( 1 )}{1 !} (x - 1) + \frac{\frac{d ^{2}}{d x ^{2}} ( 4 x ^{- 1} ) ( 1 )}{2 !} (x - 1)^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 4 x ^{- 1} ) ( 1 )}{3 !} (x - 1)^{3} + \dots

Evaluate Derivatives

= 4 + \frac{- 4}{1 !} (x - 1) + \frac{8}{2 !} (x - 1)^{2} + \frac{- 24}{3 !} (x - 1)^{3} + \frac{96}{4 !} (x - 1)^{4} + \dots

Refine

= 4 - 4 (x - 1) + 4 (x - 1)^{2} - 4 (x - 1)^{3} + 4 (x - 1)^{4} + \dots

- 4 x^{2} + 6.25 x + 8, 2.5 x + 7

\int (sec (x) - 2 x tan (x) - 2 x) d x

\frac{d}{d x} (- 2 ln (\frac{3}{2} x))

7 y^{^{'}} + 5 y = 2 e^{3 x}

f (x) = \frac{e ^{x}}{x ^{2} + 9}

What is taylor 4x^{-1} ?
The answer to taylor 4x^{-1} is 4-4(x-1)+4(x-1)^2-4(x-1)^3+4(x-1)^4+\ldots