What is the solution for y^'+sin(t)y=-sin(t),y(0)=3 ?

The solution for y^'+sin(t)y=-sin(t),y(0)=3 is y=4e^{cos(t)-1}-1

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y^'+sin(t)y=-sin(t),y(0)=3

y^{^{'}} + sin (t) y = - sin (t), y (0) = 3

y = 4 e^{c o s (t) - 1} - 1

Solution steps

y^{'} (t) + sin (t) y = - sin (t)

Solve separable ODE:

y = 4 e^{c o s (t) - 1} - 1

y = 4 e^{c o s (t) - 1} - 1

80 t^{2}

f (x) = x^{2} (1 - x)^{2}, at x = 2

x \to 0 lim (\frac{( x - 1 ) ^{2} + 1}{x})

\frac{( s + 1 ) ^{2}}{( s - 1 ) ^{3}}

\frac{\partial}{\partial x} (2 x^{2} y - 3)

What is the solution for y^'+sin(t)y=-sin(t),y(0)=3 ?
The solution for y^'+sin(t)y=-sin(t),y(0)=3 is y=4e^{cos(t)-1}-1