What is the tangent of f(x)= 7/(sqrt(x)),\at x=4 ?

The tangent of f(x)= 7/(sqrt(x)),\at x=4 is y=-7/16 x+21/4

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tangent of f(x)= 7/(sqrt(x)),\at x=4

tangent of

f (x) = \frac{7}{x}, at x = 4

y = - \frac{7}{16} x + \frac{21}{4}

Solution steps

Find the tangent point:

(4, \frac{7}{2})

Find the slope of

f (x) = \frac{7}{x} : \frac{df ( x )}{d x} = - \frac{7}{2 x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{7}{16}

Find the line with slope m=

- \frac{7}{16}

and passing through

(4, \frac{7}{2}) : y = - \frac{7}{16} x + \frac{21}{4}

y = - \frac{7}{16} x + \frac{21}{4}

f (x) = 2 x^{3} + 4 x^{2} - 5 x - 3, at x = - 1

\frac{d}{d x} (arctan (e^{3 x}))

x \to 5 lim (\frac{2}{x - 5})

\frac{d}{d x} (tan (sin (x)))

\int \frac{1}{x ^{2} 3 x ^{2} + 4} d x

What is the tangent of f(x)= 7/(sqrt(x)),\at x=4 ?
The tangent of f(x)= 7/(sqrt(x)),\at x=4 is y=-7/16 x+21/4