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Popular >

area y=x^3,y=x,x>= 0

Solution

area

y = x^{3}, y = x, x \geq 0

Solution

diverges

Solution steps

Apply the area formula:

\int_{0}^{\infty} x^{3} - x d x

Solve

\int_{0}^{\infty} x^{3} - x d x :

diverges

The area is:

= diverges

Popular Examples

integral from 0 to 1 of x^9e^{x^5}

\int_{0}^{1} x^{9} e^{x^{5}} d x

limit as x approaches 0 of ((ln(cos(2x))))/(x^2)

x \to 0 lim (\frac{( ln ( cos ( 2 x ) ) )}{x ^{2}})

x^2y^{''}+9xy^'-20y= 5/(x^3)

x^{2} y^{^{''}} + 9 x y^{^{'}} - 20 y = \frac{5}{x ^{3}}

derivative of f(x)=csc(x)(x+cot(x))derivative of

f (x) = csc (x) (x + cot (x))

limit as x approaches 0 of 1/(x+5)

x \to 0 lim (\frac{1}{x + 5})

Frequently Asked Questions (FAQ)

What is area y=x^3,y=x,x>= 0 ?
The answer to area y=x^3,y=x,x>= 0 is diverges