What is the integral from 4 to 6 of 1 ?

The integral from 4 to 6 of 1 is 2

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integral from 4 to 6 of 1

\int_{4}^{6} 1

2

Solution steps

\int_{4}^{6} 1 d x

Integral of a constant:

\int a d x = a x

= [1 \cdot x]_{4}^{6}

Simplify

= [x]_{4}^{6}

Compute the boundaries:

2

= 2

\frac{d}{d x} (\frac{3}{2 x + 1})

\frac{d}{d x} (\frac{x ^{2} + 2 x + 1}{x ^{2} - 2 x + 1})

\frac{d}{d x} ((3 x + 5) x^{2})

y^{^{''}} - 6 y^{^{'}} + 8 y = 0

\int sin^{7} (x) cos^{2} (x) d x