What is the derivative of (3x-y)/x ?

The derivative of (3x-y)/x is y/(x^2)

What is the first derivative of (3x-y)/x ?

The first derivative of (3x-y)/x is y/(x^2)

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derivative of

\frac{3 x - y}{x}

\frac{y}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{3 x - y}{x})

Treat

y

as a constant

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 3 x - y ) x - \frac{d x}{d x} ( 3 x - y )}{x ^{2}}

\frac{d}{d x} (3 x - y) = 3

\frac{d x}{d x} = 1

= \frac{3 x - 1 \cdot ( 3 x - y )}{x ^{2}}

Simplify

= \frac{y}{x ^{2}}

\frac{\partial}{\partial x} (x^{0.2} y^{0.4})

x \to 3 lim (\frac{3 - x}{x ^{2} - 9})

\int \frac{1}{x ^{2} + 4 x + 20} d x

f (t) = t sin (π t)

\int x^{2} tan (x^{3}) d x

What is the derivative of (3x-y)/x ?
The derivative of (3x-y)/x is y/(x^2)
What is the first derivative of (3x-y)/x ?
The first derivative of (3x-y)/x is y/(x^2)