What is the limit as q approaches 18 of 0.9q^2-6q+80 ?

The limit as q approaches 18 of 0.9q^2-6q+80 is 263.6

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limit as q approaches 18 of 0.9q^2-6q+80

q \to 18 lim (0.9 q^{2} - 6 q + 80)

263.6

Solution steps

q \to 18 lim (0.9 q^{2} - 6 q + 80)

Plug in the value

q = 18

= 0.9 \cdot 1 8^{2} - 6 \cdot 18 + 80

Simplify

0.9 \cdot 1 8^{2} - 6 \cdot 18 + 80 : 263.6

= 263.6

sec (θ) (θ - tan (θ))

x^{2} + 8

f (x) = x^{2} - 10 x + 34 + x^{2} + 16

\int (x - \frac{3}{x})^{2} x d x

\frac{\partial}{\partial x} (x ln (y) + y^{2} ln (x))

What is the limit as q approaches 18 of 0.9q^2-6q+80 ?
The limit as q approaches 18 of 0.9q^2-6q+80 is 263.6