What is the integral of 10cos(sqrt(4x)) ?

The integral of 10cos(sqrt(4x)) is 5(2sqrt(x)sin(2sqrt(x))+cos(2sqrt(x)))+C

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integral of 10cos(sqrt(4x))

\int 10 cos (4 x) d x

5 (2 x sin (2 x) + cos (2 x)) + C

Solution steps

\int 10 cos (4 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int cos (4 x) d x

Apply u-substitution

: \int cos (u) \frac{1}{4} d u

= 10 \cdot \int cos (u) \frac{1}{4} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \frac{1}{4} \cdot \int cos (u) d u

Apply u-substitution

: \int cos (v) \cdot 2 v d v

= 10 \cdot \frac{1}{4} \cdot \int cos (v) \cdot 2 v d v

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \frac{1}{4} \cdot 2 \cdot \int cos (v) v d v

Apply Integration By Parts

: v sin (v) - \int sin (v) d v

= 10 \cdot \frac{1}{4} \cdot 2 (v sin (v) - \int sin (v) d v)

\int sin (v) d v = - cos (v)

= 10 \cdot \frac{1}{4} \cdot 2 (v sin (v) - (- cos (v)))

Substitute back

= 10 \cdot \frac{1}{4} \cdot 2 (4 x sin (4 x) - (- cos (4 x)))

Simplify

10 \cdot \frac{1}{4} \cdot 2 (4 x sin (4 x) - (- cos (4 x))) : 5 (2 x sin (2 x) + cos (2 x))

= 5 (2 x sin (2 x) + cos (2 x))

Add a constant to the solution

= 5 (2 x sin (2 x) + cos (2 x)) + C

x \to 1 lim (x^{3} + 2 x^{2} - x - 10)

\frac{d}{d x} (x z (x) (x)^{2})

\frac{d}{d x} (\frac{9}{5 x ^{2}})

\int 10 cos^{3} (x) d x

f (x) = \frac{4}{8 x + 7}

What is the integral of 10cos(sqrt(4x)) ?
The integral of 10cos(sqrt(4x)) is 5(2sqrt(x)sin(2sqrt(x))+cos(2sqrt(x)))+C