What is the derivative of f(x)= 4/(8x+7) ?

The derivative of f(x)= 4/(8x+7) is -(32)/((8x+7)^2)

What is the first derivative of f(x)= 4/(8x+7) ?

The first derivative of f(x)= 4/(8x+7) is -(32)/((8x+7)^2)

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derivative of

f (x) = \frac{4}{8 x + 7}

- \frac{32}{( 8 x + 7 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{4}{8 x + 7})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 4 \frac{d}{d x} (\frac{1}{8 x + 7})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 4 \frac{d}{d x} ((8 x + 7)^{- 1})

Apply the chain rule:

- \frac{1}{( 8 x + 7 ) ^{2}} \frac{d}{d x} (8 x + 7)

= - \frac{1}{( 8 x + 7 ) ^{2}} \frac{d}{d x} (8 x + 7)

\frac{d}{d x} (8 x + 7) = 8

= 4 (- \frac{1}{( 8 x + 7 ) ^{2}} \cdot 8)

Simplify

4 (- \frac{1}{( 8 x + 7 ) ^{2}} \cdot 8) : - \frac{32}{( 8 x + 7 ) ^{2}}

= - \frac{32}{( 8 x + 7 ) ^{2}}

x \to 0 lim (\frac{8 sin ( 3 x )}{1 - cos ( 3 x )})

\frac{d}{d x} (2 e^{2 x} x + e^{2 x})

\int_{1}^{2} (\frac{x}{y} + \frac{y}{x}) d y

\int_{0}^{3} x 1 + x d x

\frac{d}{d x} (\frac{1}{x ^{2}} - 3 x^{2})

What is the derivative of f(x)= 4/(8x+7) ?
The derivative of f(x)= 4/(8x+7) is -(32)/((8x+7)^2)
What is the first derivative of f(x)= 4/(8x+7) ?
The first derivative of f(x)= 4/(8x+7) is -(32)/((8x+7)^2)