What is the integral from 1 to 2 of (x/y+y/x) ?

The integral from 1 to 2 of (x/y+y/x) is xln(2)+3/(2x)

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integral from 1 to 2 of (x/y+y/x)

\int_{1}^{2} (\frac{x}{y} + \frac{y}{x}) d y

x ln (2) + \frac{3}{2 x}

Solution steps

\int_{1}^{2} \frac{x}{y} + \frac{y}{x} d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} \frac{x}{y} d y + \int_{1}^{2} \frac{y}{x} d y

\int_{1}^{2} \frac{x}{y} d y = x ln (2)

\int_{1}^{2} \frac{y}{x} d y = \frac{3}{2 x}

= x ln (2) + \frac{3}{2 x}

\int_{0}^{3} x 1 + x d x

\frac{d}{d x} (\frac{1}{x ^{2}} - 3 x^{2})

\int (2 + y^{2})^{2} d y

\frac{( 6 x ^{9} + x ^{8} )}{2 x ^{4}}

\frac{\partial}{\partial x} (y + 2 x)

What is the integral from 1 to 2 of (x/y+y/x) ?
The integral from 1 to 2 of (x/y+y/x) is xln(2)+3/(2x)