What is the derivative of 2x^2-3x+4 ?

The derivative of 2x^2-3x+4 is 4x-3

What is the first derivative of 2x^2-3x+4 ?

The first derivative of 2x^2-3x+4 is 4x-3

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\frac{d}{d x} (2 x^{2} - 3 x + 4)

4 x - 3

Solution steps

\frac{d}{d x} (2 x^{2} - 3 x + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (3 x) + \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (3 x) = 3

\frac{d}{d x} (4) = 0

= 4 x - 3 + 0

Simplify

= 4 x - 3

\int \frac{x}{x ^{2} - 4 x + 5} d x

f (x) = \frac{x ^{4}}{2}

\frac{\partial}{\partial y} (\frac{- x}{y})

\int \frac{y + 2}{y} d y

n = 1 \sum \infty \frac{( - 1 ) ^{n - 1}}{n n}

What is the derivative of 2x^2-3x+4 ?
The derivative of 2x^2-3x+4 is 4x-3
What is the first derivative of 2x^2-3x+4 ?
The first derivative of 2x^2-3x+4 is 4x-3