What is (\partial)/(\partial x)(3x^2+2y^4) ?

The answer to (\partial)/(\partial x)(3x^2+2y^4) is 6x

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(\partial)/(\partial x)(3x^2+2y^4)

\frac{\partial}{\partial x} (3 x^{2} + 2 y^{4})

6 x

Solution steps

\frac{\partial}{\partial x} (3 x^{2} + 2 y^{4})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (3 x^{2}) + \frac{\partial}{\partial x} (2 y^{4})

\frac{\partial}{\partial x} (3 x^{2}) = 6 x

\frac{\partial}{\partial x} (2 y^{4}) = 0

= 6 x + 0

Simplify

= 6 x

x \to 0 lim (lo g_{e} (1 + x))

\int sin (x) (1 + sec^{2} (x)) d x

\frac{d x}{d t} = 1.5 t cos^{2} (x), x (0) = - 1.4

f (x) = 4 x - 4 x

n = 2 \sum \infty \frac{7}{6 ^{n}}

What is (\partial)/(\partial x)(3x^2+2y^4) ?
The answer to (\partial)/(\partial x)(3x^2+2y^4) is 6x