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Popular >

y^'-y-e^{3x}=0

Solution

y^{^{'}} - y - e^{3 x} = 0

Solution

y = \frac{e ^{3 x}}{2} + c_{1} e^{x}

Solution steps

y^{'} (x) - y - e^{3 x} = 0

Solve linear ODE:

y = \frac{e ^{3 x}}{2} + c_{1} e^{x}

y = \frac{e ^{3 x}}{2} + c_{1} e^{x}

Popular Examples

tangent of f(x)=9x^2-2x tangent of

f (x) = 9 x^{2} - 2 x

derivative of f(x)=sqrt(7x+6)derivative of

f (x) = 7 x + 6

derivative of 5cos(4x)

\frac{d}{d x} (5 cos (4 x))

integral of (3x+5)/(sqrt(x^2+x+1))

\int \frac{3 x + 5}{x ^{2} + x + 1} d x

integral of t/(sqrt(1-t^4))

\int \frac{t}{1 - t ^{4}} d t

Frequently Asked Questions (FAQ)

What is the solution for y^'-y-e^{3x}=0 ?
The solution for y^'-y-e^{3x}=0 is y=(e^{3x})/2+c_{1}e^x