What is the sum from n=0 to infinity of (e^n)/(3^n) ?

The sum from n=0 to infinity of (e^n)/(3^n) is converges

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sum from n=0 to infinity of (e^n)/(3^n)

n = 0 \sum \infty \frac{e ^{n}}{3 ^{n}}

converges

Solution steps

n = 0 \sum \infty \frac{e ^{n}}{3 ^{n}}

Apply Series Ratio Test:

converges

= converges

\int_{\frac{1}{3}}^{1} \frac{y + 4}{y ^{2} + 2 y} d y

x \to \frac{3 π}{2} lim (ln (1 + sin (x)))

\frac{d}{d y} (2 x + 3 y)

\int_{4}^{8} \frac{x}{x ^{2} - 1} d x

What is the sum from n=0 to infinity of (e^n)/(3^n) ?
The sum from n=0 to infinity of (e^n)/(3^n) is converges