What is (\partial)/(\partial x)(sin(x^2-3xy)) ?

The answer to (\partial)/(\partial x)(sin(x^2-3xy)) is cos(x^2-3xy)(2x-3y)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(sin(x^2-3xy))

\frac{\partial}{\partial x} (sin (x^{2} - 3 x y))

cos (x^{2} - 3 x y) (2 x - 3 y)

Solution steps

\frac{\partial}{\partial x} (sin (x^{2} - 3 x y))

Treat

y

as a constant

Apply the chain rule:

cos (x^{2} - 3 x y) \frac{\partial}{\partial x} (x^{2} - 3 x y)

= cos (x^{2} - 3 x y) \frac{\partial}{\partial x} (x^{2} - 3 x y)

\frac{\partial}{\partial x} (x^{2} - 3 x y) = 2 x - 3 y

= cos (x^{2} - 3 x y) (2 x - 3 y)

\int_{2}^{5} \frac{1}{x - 3} d x

\frac{( x ^{2} + 3 x )}{( 2 x + 3 ) ^{3}}

\int ln (x + x^{2}) d x

\int x^{2} (7 - x^{3})^{\frac{2}{3}} d x

\frac{d}{d x} (tan (x^{2} - 4 x))

What is (\partial)/(\partial x)(sin(x^2-3xy)) ?
The answer to (\partial)/(\partial x)(sin(x^2-3xy)) is cos(x^2-3xy)(2x-3y)