What is the derivative of 1/((x-2^2)) ?

The derivative of 1/((x-2^2)) is -2/((x-2)^3)

What is the first derivative of 1/((x-2^2)) ?

The first derivative of 1/((x-2^2)) is -2/((x-2)^3)

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\frac{d}{d x} (\frac{1}{( x - 2 ) ^{2}})

- \frac{2}{( x - 2 ) ^{3}}

Solution steps

\frac{d}{d x} (\frac{1}{( x - 2 ) ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{d}{d x} ((x - 2)^{- 2})

Apply the chain rule:

- \frac{2}{( x - 2 ) ^{3}} \frac{d}{d x} (x - 2)

= - \frac{2}{( x - 2 ) ^{3}} \frac{d}{d x} (x - 2)

\frac{d}{d x} (x - 2) = 1

= - \frac{2}{( x - 2 ) ^{3}} \cdot 1

Simplify

= - \frac{2}{( x - 2 ) ^{3}}

f (x) = x^{2} + 2 x + 1, at x = - 3

(8 - 4) (89)

\frac{d}{d x} (x^{2} - sin (x))

x^{2} + y^{2} = 169, (5, - 12)

\int \frac{x - arctan ( x )}{x} d x

What is the derivative of 1/((x-2^2)) ?
The derivative of 1/((x-2^2)) is -2/((x-2)^3)
What is the first derivative of 1/((x-2^2)) ?
The first derivative of 1/((x-2^2)) is -2/((x-2)^3)