What is the tangent of x^2+y^2=169,(5,-12) ?

The tangent of x^2+y^2=169,(5,-12) is y= 5/12 x-169/12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

tangent of x^2+y^2=169,(5,-12)

tangent of

x^{2} + y^{2} = 169, (5, - 12)

y = \frac{5}{12} x - \frac{169}{12}

Solution steps

Find the slope of

x^{2} + y^{2} = 169 : \frac{d y}{d x} = - \frac{x}{y}

Compute the slope of

x^{2} + y^{2} = 169

(5, - 12) : m = \frac{5}{12}

Find the line with slope m=

\frac{5}{12}

and passing through

(5, - 12) : y = \frac{5}{12} x - \frac{169}{12}

y = \frac{5}{12} x - \frac{169}{12}

\int \frac{x - arctan ( x )}{x} d x

f (x) = lo g_{10} (x + 1)

y^{^{''}} + 2 y^{^{'}} + 10 y = 5 x e^{(- 2 x)}

\frac{2}{x ^{3} + 2}

f (x) = x^{2} - 9

What is the tangent of x^2+y^2=169,(5,-12) ?
The tangent of x^2+y^2=169,(5,-12) is y= 5/12 x-169/12