What is the derivative of 9e^xcos(x) ?

The derivative of 9e^xcos(x) is 9(e^xcos(x)-e^xsin(x))

What is the first derivative of 9e^xcos(x) ?

The first derivative of 9e^xcos(x) is 9(e^xcos(x)-e^xsin(x))

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derivative of

9 e^{x} cos (x)

9 (e^{x} cos (x) - e^{x} sin (x))

Solution steps

\frac{d}{d x} (9 e^{x} cos (x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 9 \frac{d}{d x} (e^{x} cos (x))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = e^{x}, g = cos (x)

= 9 (\frac{d}{d x} (e^{x}) cos (x) + \frac{d}{d x} (cos (x)) e^{x})

\frac{d}{d x} (e^{x}) = e^{x}

\frac{d}{d x} (cos (x)) = - sin (x)

= 9 (e^{x} cos (x) + (- sin (x)) e^{x})

Simplify

= 9 (e^{x} cos (x) - e^{x} sin (x))

\frac{s + 3}{( s - 2 ) ( s + 1 )}

x \to 1 lim (2 - x^{2})

\frac{d x}{d y} - sin (x + y) = 0

5^{6 x}

y = 15 x ln (13 x)

What is the derivative of 9e^xcos(x) ?
The derivative of 9e^xcos(x) is 9(e^xcos(x)-e^xsin(x))
What is the first derivative of 9e^xcos(x) ?
The first derivative of 9e^xcos(x) is 9(e^xcos(x)-e^xsin(x))