What is the solution for (dx)/(dy)-sin(x+y)=0 ?

The solution for (dx)/(dy)-sin(x+y)=0 is x=2arctan((-2-y-c_{1})/(y+c_{1)})+2pin-y

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(dx)/(dy)-sin(x+y)=0

\frac{d x}{d y} - sin (x + y) = 0

x = 2 arctan (\frac{- 2 - y - c _{1}}{y + c _{1}}) + 2 πn - y

Solution steps

\frac{d x}{d y} - sin (x + y) = 0

Solve using substitution:

x = 2 arctan (\frac{- 2 - y - c _{1}}{y + c _{1}}) + 2 πn - y

x = 2 arctan (\frac{- 2 - y - c _{1}}{y + c _{1}}) + 2 πn - y

5^{6 x}

y = 15 x ln (13 x)

\int x \cdot sin^{2} (x) d x

\int_{0}^{2} y^{2} d y

\frac{d}{d x} (- 2 sin (x^{2}) - 4 x^{2} cos (x^{2}))

What is the solution for (dx)/(dy)-sin(x+y)=0 ?
The solution for (dx)/(dy)-sin(x+y)=0 is x=2arctan((-2-y-c_{1})/(y+c_{1)})+2pin-y