What is the integral from 0 to 2 of y^2 ?

The integral from 0 to 2 of y^2 is 8/3

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integral from 0 to 2 of y^2

\int_{0}^{2} y^{2} d y

\frac{8}{3}

Decimal Notation

2.66666 \dots

Solution steps

\int_{0}^{2} y^{2} d y

Apply the Power Rule

: [\frac{y ^{3}}{3}]_{0}^{2}

= [\frac{y ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= \frac{8}{3}

\frac{d}{d x} (- 2 sin (x^{2}) - 4 x^{2} cos (x^{2}))

\int \frac{1}{x ^{2} + x - 12} d x

t e^{- t}

\frac{d}{d x} (\frac{2 x ^{5} + 3 x ^{4} - 1}{- 2 x ^{7}})

\frac{d}{d x} (x^{3} + 2 x^{2} + x - 7)

What is the integral from 0 to 2 of y^2 ?
The integral from 0 to 2 of y^2 is 8/3