What is the derivative of ((x+1)^2)/((3x-4)) ?

The derivative of ((x+1)^2)/((3x-4)) is (3x^2-8x-11)/((3x-4)^2)

What is the first derivative of ((x+1)^2)/((3x-4)) ?

The first derivative of ((x+1)^2)/((3x-4)) is (3x^2-8x-11)/((3x-4)^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

\frac{( x + 1 ) ^{2}}{( 3 x - 4 )}

\frac{3 x ^{2} - 8 x - 11}{( 3 x - 4 ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{( x + 1 ) ^{2}}{3 x - 4})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( ( x + 1 ) ^{2} ) ( 3 x - 4 ) - \frac{d}{d x} ( 3 x - 4 ) ( x + 1 ) ^{2}}{( 3 x - 4 ) ^{2}}

\frac{d}{d x} ((x + 1)^{2}) = 2 (x + 1)

\frac{d}{d x} (3 x - 4) = 3

= \frac{2 ( x + 1 ) ( 3 x - 4 ) - 3 ( x + 1 ) ^{2}}{( 3 x - 4 ) ^{2}}

Expand

2 (x + 1) (3 x - 4) - 3 (x + 1)^{2} : 3 x^{2} - 8 x - 11

= \frac{3 x ^{2} - 8 x - 11}{( 3 x - 4 ) ^{2}}

\int \frac{4 x ^{3} - 3 x}{( x ^{2} + 1 ) ^{2}} d x

\int_{2}^{3} x^{2} e^{x^{3} - 8} d x

\frac{x ^{2}}{x + 7}

49 y^{^{''}} - 16 y = 0

\frac{3 ^{2}}{( s + 3 ) ^{2}}

What is the derivative of ((x+1)^2)/((3x-4)) ?
The derivative of ((x+1)^2)/((3x-4)) is (3x^2-8x-11)/((3x-4)^2)
What is the first derivative of ((x+1)^2)/((3x-4)) ?
The first derivative of ((x+1)^2)/((3x-4)) is (3x^2-8x-11)/((3x-4)^2)