What is the solution for y^{''}=36x^7+21x^5-3x+48x^{-5} ?

The solution for y^{''}=36x^7+21x^5-3x+48x^{-5} is y=(x^9)/2+(x^7)/2-(x^3)/2+4/(x^3)+c_{1}x+c_{2}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}=36x^7+21x^5-3x+48x^{-5}

y^{^{''}} = 36 x^{7} + 21 x^{5} - 3 x + 48 x^{- 5}

y = \frac{x ^{9}}{2} + \frac{x ^{7}}{2} - \frac{x ^{3}}{2} + \frac{4}{x ^{3}} + c_{1} x + c_{2}

Solution steps

y^{''} (x) = 36 x^{7} + 21 x^{5} - 3 x + 48 x^{- 5}

Solve

y^{''} (x) = 36 x^{7} + 21 x^{5} - 3 x + 48 x^{- 5} : y^{'} (x) = \frac{9 x ^{8}}{2} + \frac{7 x ^{6}}{2} - \frac{3 x ^{2}}{2} - \frac{12}{x ^{4}} + c_{1}

Solve

y^{'} (x) = \frac{9 x ^{8}}{2} + \frac{7 x ^{6}}{2} - \frac{3 x ^{2}}{2} - \frac{12}{x ^{4}} + c_{1} : y = \frac{x ^{9}}{2} + \frac{x ^{7}}{2} - \frac{x ^{3}}{2} + \frac{4}{x ^{3}} + c_{1} x + c_{2}

y = \frac{x ^{9}}{2} + \frac{x ^{7}}{2} - \frac{x ^{3}}{2} + \frac{4}{x ^{3}} + c_{1} x + c_{2}

sin (x), 1

\frac{d}{d x} (3 sin (2 x) + cos (2 x))

y = x (3 x + 2)^{5}

f (x) = \frac{8}{x ^{2} + x + 2}, at x = 2

t^{2} \frac{d y}{d t} + 4 t y - y^{3} = 0

What is the solution for y^{''}=36x^7+21x^5-3x+48x^{-5} ?
The solution for y^{''}=36x^7+21x^5-3x+48x^{-5} is y=(x^9)/2+(x^7)/2-(x^3)/2+4/(x^3)+c_{1}x+c_{2}