What is the derivative of (x^4+1^{1/2}) ?

The derivative of (x^4+1^{1/2}) is (2x^3)/((x^4+1)^{1/2)}

What is the first derivative of (x^4+1^{1/2}) ?

The first derivative of (x^4+1^{1/2}) is (2x^3)/((x^4+1)^{1/2)}

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\frac{d}{d x} ((x^{4} + 1)^{\frac{1}{2}})

\frac{2 x ^{3}}{( x ^{4} + 1 ) ^{\frac{1}{2}}}

Solution steps

\frac{d}{d x} ((x^{4} + 1)^{\frac{1}{2}})

Apply the chain rule:

\frac{1}{2 ( x ^{4} + 1 ) ^{\frac{1}{2}}} \frac{d}{d x} (x^{4} + 1)

= \frac{1}{2 ( x ^{4} + 1 ) ^{\frac{1}{2}}} \frac{d}{d x} (x^{4} + 1)

\frac{d}{d x} (x^{4} + 1) = 4 x^{3}

= \frac{1}{2 ( x ^{4} + 1 ) ^{\frac{1}{2}}} \cdot 4 x^{3}

Simplify

\frac{1}{2 ( x ^{4} + 1 ) ^{\frac{1}{2}}} \cdot 4 x^{3} : \frac{2 x ^{3}}{( x ^{4} + 1 ) ^{\frac{1}{2}}}

= \frac{2 x ^{3}}{( x ^{4} + 1 ) ^{\frac{1}{2}}}

\int 2 z d z

\frac{7 x - 1}{x ^{2} + 9 x}

\int_{- 11}^{0} x 25 - x d x

\frac{d}{d x} (x^{2} + 2 x y + y^{2})

\frac{\partial}{\partial x} (4 sin (x))

What is the derivative of (x^4+1^{1/2}) ?
The derivative of (x^4+1^{1/2}) is (2x^3)/((x^4+1)^{1/2)}
What is the first derivative of (x^4+1^{1/2}) ?
The first derivative of (x^4+1^{1/2}) is (2x^3)/((x^4+1)^{1/2)}