What is the (sqrt(x-1))^' ?

The (sqrt(x-1))^' is 1/(2sqrt(x-1))

What is the first (sqrt(x-1))^' ?

The first (sqrt(x-1))^' is 1/(2sqrt(x-1))

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(x - 1)^{^{'}}

\frac{1}{2 x - 1}

Solution steps

(x - 1)^{'}

Apply the chain rule:

\frac{1}{2 x - 1} (x - 1)^{'}

= \frac{1}{2 x - 1} (x - 1)^{'}

(x - 1)^{'} = 1

= \frac{1}{2 x - 1} \cdot 1

Simplify

= \frac{1}{2 x - 1}

\frac{d}{d x} (\frac{( a x + b )}{( c x + d )})

\int \frac{7}{3 + 7 x ^{2}} d x

n = 2 \sum \infty n e^{- n}

f (x) = e^{4 a} (4 a^{3} - 3)

\frac{d}{d x} (ln (tan (x)))