What is the derivative of (x^2+2^3) ?

The derivative of (x^2+2^3) is 6x(x^2+2)^2

What is the first derivative of (x^2+2^3) ?

The first derivative of (x^2+2^3) is 6x(x^2+2)^2

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\frac{d}{d x} ((x^{2} + 2)^{3})

6 x (x^{2} + 2)^{2}

Solution steps

\frac{d}{d x} ((x^{2} + 2)^{3})

Apply the chain rule:

3 (x^{2} + 2)^{2} \frac{d}{d x} (x^{2} + 2)

= 3 (x^{2} + 2)^{2} \frac{d}{d x} (x^{2} + 2)

\frac{d}{d x} (x^{2} + 2) = 2 x

= 3 (x^{2} + 2)^{2} \cdot 2 x

Simplify

= 6 x (x^{2} + 2)^{2}

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h \to 0 lim (\frac{( 1 + h ) ^{4} - 1}{h})

\int \frac{x ^{2}}{64 + x ^{2}} d x

What is the derivative of (x^2+2^3) ?
The derivative of (x^2+2^3) is 6x(x^2+2)^2
What is the first derivative of (x^2+2^3) ?
The first derivative of (x^2+2^3) is 6x(x^2+2)^2