What is the solution for t^2(dx)/(dt)= 1/(x^2),x(4)=9 ?

The solution for t^2(dx)/(dt)= 1/(x^2),x(4)=9 is x=\sqrt[3]{-3/t+2919/4}

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t^2(dx)/(dt)= 1/(x^2),x(4)=9

t^{2} \frac{d x}{d t} = \frac{1}{x ^{2}}, x (4) = 9

Solution steps

t^{2} \frac{d x}{d t} = \frac{1}{x ^{2}}

Solve separable ODE:

\int sin^{2} (u) d u

\frac{\partial}{\partial z} (x \cdot y^{2} \cdot e^{z})

\frac{d}{d x} (3 x^{2} + 6 x + cos (x))

f (x) = \frac{7}{x}

x \to \infty lim (- 1 + \frac{1}{x})

What is the solution for t^2(dx)/(dt)= 1/(x^2),x(4)=9 ?
The solution for t^2(dx)/(dt)= 1/(x^2),x(4)=9 is x=\sqrt[3]{-3/t+2919/4}