What is the sum from n=1,3,5 to infinity of 1/(n^2) ?

The sum from n=1,3,5 to infinity of 1/(n^2) is converges

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sum from n=1,3,5 to infinity of 1/(n^2)

n = 1, 3, 5 \sum \infty \frac{1}{n ^{2}}

converges

Solution steps

n = 1, 3, 5 \sum \infty \frac{1}{n ^{2}}

Apply p-Series Test:

converges

= converges

f (x) = \frac{5 x}{x + 4}, (1, 1)

\frac{d}{d x} (\frac{b}{x ^{2}})

x \to 2 lim (\frac{( 3 x + 2 )}{5 x - 2})^{\frac{( 3 )}{x - 2}}

\int (x - 2) 2 d x

x \to \infty lim (x^{6} e^{- x^{5}})

What is the sum from n=1,3,5 to infinity of 1/(n^2) ?
The sum from n=1,3,5 to infinity of 1/(n^2) is converges