What is the derivative of-2/((1-x^3)) ?

The derivative of-2/((1-x^3)) is -6/((1-x)^4)

What is the first derivative of-2/((1-x^3)) ?

The first derivative of-2/((1-x^3)) is -6/((1-x)^4)

Popular >

\frac{d}{d x} (- \frac{2}{( 1 - x ) ^{3}})

- \frac{6}{( 1 - x ) ^{4}}

Solution steps

\frac{d}{d x} (- \frac{2}{( 1 - x ) ^{3}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 2 \frac{d}{d x} (\frac{1}{( 1 - x ) ^{3}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= - 2 \frac{d}{d x} ((1 - x)^{- 3})

Apply the chain rule:

- \frac{3}{( 1 - x ) ^{4}} \frac{d}{d x} (1 - x)

= - \frac{3}{( 1 - x ) ^{4}} \frac{d}{d x} (1 - x)

\frac{d}{d x} (1 - x) = - 1

= - 2 (- \frac{3}{( 1 - x ) ^{4}} (- 1))

Simplify

- 2 (- \frac{3}{( 1 - x ) ^{4}} (- 1)) : - \frac{6}{( 1 - x ) ^{4}}

= - \frac{6}{( 1 - x ) ^{4}}

\frac{\partial}{\partial x} ((x + z - y)^{2})

(t^{2} + \frac{1}{2})^{2}

(x^{2} + 2 y^{2}) d x - x y d y = 0

\frac{\partial}{\partial x} (x e^{\frac{s}{x}})

\int \frac{( 4 x ^{2} + 2 )}{( x ^{2} - 2 x + 2 ) ^{2}} d x

What is the derivative of-2/((1-x^3)) ?
The derivative of-2/((1-x^3)) is -6/((1-x)^4)
What is the first derivative of-2/((1-x^3)) ?
The first derivative of-2/((1-x^3)) is -6/((1-x)^4)