What is the tangent of y=2sin(x),\at x= 3/4 pi ?

The tangent of y=2sin(x),\at x= 3/4 pi is y=-sqrt(2)x+sqrt(2)+(3pi)/(2sqrt(2))

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tangent of y=2sin(x),\at x= 3/4 pi

tangent of

y = 2 sin (x), at x = \frac{3}{4} π

y = - 2 x + 2 + \frac{3 π}{2 2}

Solution steps

Find the tangent point:

(\frac{3}{4} π, 2)

Find the slope of

y = 2 sin (x) : \frac{d y}{d x} = 2 cos (x)

Compute the slope of

y = 2 sin (x)

x = \frac{3}{4} π : m = - 2

Find the line with slope m=

- 2

and passing through

(\frac{3}{4} π, 2) : y = - 2 x + 2 + \frac{3 π}{2 2}

y = - 2 x + 2 + \frac{3 π}{2 2}

h (x) = \frac{3 x ^{3} - 3}{ln ( x )}

f (x) = 1 - 2 x + x^{2}

f (T) = T

y = \frac{3}{x}, y = 9 x, y = \frac{1}{9 x}

What is the tangent of y=2sin(x),\at x= 3/4 pi ?
The tangent of y=2sin(x),\at x= 3/4 pi is y=-sqrt(2)x+sqrt(2)+(3pi)/(2sqrt(2))