What is the derivative of f(x)=1-2x+x^2 ?

The derivative of f(x)=1-2x+x^2 is 2x-2

What is the first derivative of f(x)=1-2x+x^2 ?

The first derivative of f(x)=1-2x+x^2 is 2x-2

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derivative of

f (x) = 1 - 2 x + x^{2}

2 x - 2

Solution steps

\frac{d}{d x} (1 - 2 x + x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) - \frac{d}{d x} (2 x) + \frac{d}{d x} (x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (2 x) = 2

\frac{d}{d x} (x^{2}) = 2 x

= 0 - 2 + 2 x

Simplify

= 2 x - 2

f (T) = T

y = \frac{3}{x}, y = 9 x, y = \frac{1}{9 x}

4 sin (3 t)

\frac{\partial}{\partial x} (sin (x^{2} + 2 y))

What is the derivative of f(x)=1-2x+x^2 ?
The derivative of f(x)=1-2x+x^2 is 2x-2
What is the first derivative of f(x)=1-2x+x^2 ?
The first derivative of f(x)=1-2x+x^2 is 2x-2