What is laplacetransform 4sin(3t) ?

The answer to laplacetransform 4sin(3t) is (12)/(s^2+9)

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laplacetransform 4sin(3t)

laplace transform

4 sin (3 t)

\frac{12}{s ^{2} + 9}

Solution steps

L {4 sin (3 t)}

Use the constant multiplication property of Laplace Transform:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 4 L {sin (3 t)}

L {sin (3 t)} : \frac{3}{s ^{2} + 9}

= 4 \cdot \frac{3}{s ^{2} + 9}

Refine

4 \frac{3}{s ^{2} + 9} : \frac{12}{s ^{2} + 9}

= \frac{12}{s ^{2} + 9}

\frac{\partial}{\partial x} (sin (x^{2} + 2 y))

\int_{- \frac{π}{2}}^{\frac{π}{2}} cos (x) d x

\int \frac{22}{22 + e ^{x}} d x

f (x) = 9 - x^{2}, (3, 0)

\frac{d}{d y} (y \cdot e^{x \cdot y})

What is laplacetransform 4sin(3t) ?
The answer to laplacetransform 4sin(3t) is (12)/(s^2+9)