What is the integral from-infinity to 0 of xe^{-x^2} ?

The integral from-infinity to 0 of xe^{-x^2} is -1/2

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integral from-infinity to 0 of xe^{-x^2}

\int_{- \infty}^{0} x e^{- x^{2}} d x

- \frac{1}{2}

Decimal Notation

- 0.5

Solution steps

\int_{- \infty}^{0} x e^{- x^{2}} d x

Compute the indefinite integral:

\int x e^{- x^{2}} d x = - \frac{1}{2} e^{- x^{2}} + C

Compute the boundaries:

\int_{- \infty}^{0} x e^{- x^{2}} d x = - \frac{1}{2} - 0

= - \frac{1}{2} - 0

Simplify

= - \frac{1}{2}

\frac{\partial}{\partial x} (x - 3 y)

f (x) = 4 x^{2} - 3 x

6 t e^{- t}

f (x) = \frac{1}{5 ( 4 )}

\frac{d}{d x} (\frac{e ^{2 - x} - 2 x}{e ^{2 - x} + 3 x})

What is the integral from-infinity to 0 of xe^{-x^2} ?
The integral from-infinity to 0 of xe^{-x^2} is -1/2