What is the derivative of (x-sqrt(x)/(x^2)) ?

The derivative of (x-sqrt(x)/(x^2)) is (-2sqrt(x)+3)/(2x^{5/2)}

What is the first derivative of (x-sqrt(x)/(x^2)) ?

The first derivative of (x-sqrt(x)/(x^2)) is (-2sqrt(x)+3)/(2x^{5/2)}

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\frac{d}{d x} (\frac{x - x}{x ^{2}})

\frac{- 2 x + 3}{2 x ^{\frac{5}{2}}}

Solution steps

\frac{d}{d x} (\frac{x - x}{x ^{2}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( x - x ) x ^{2} - \frac{d}{d x} ( x ^{2} ) ( x - x )}{( x ^{2} ) ^{2}}

\frac{d}{d x} (x - x) = 1 - \frac{1}{2 x}

\frac{d}{d x} (x^{2}) = 2 x

= \frac{( 1 - \frac{1}{2 x} ) x ^{2} - 2 x ( x - x )}{( x ^{2} ) ^{2}}

Simplify

\frac{( 1 - \frac{1}{2 x} ) x ^{2} - 2 x ( x - x )}{( x ^{2} ) ^{2}} : \frac{- 2 x + 3}{2 x ^{\frac{5}{2}}}

= \frac{- 2 x + 3}{2 x ^{\frac{5}{2}}}

\int \frac{x ^{2}}{x ^{2} - 6 x + 9} d x

y = \frac{∣ x ∣}{5 - x ^{2}}, (2, 2)

\frac{2 x ^{2} - 7}{8 x ^{3} + 1}

\frac{d}{d x} (\frac{x ^{2} + y ^{2} - 9}{x})

n = 1 \sum \infty \frac{- 1 ^{n + 1}}{n}

What is the derivative of (x-sqrt(x)/(x^2)) ?
The derivative of (x-sqrt(x)/(x^2)) is (-2sqrt(x)+3)/(2x^{5/2)}
What is the first derivative of (x-sqrt(x)/(x^2)) ?
The first derivative of (x-sqrt(x)/(x^2)) is (-2sqrt(x)+3)/(2x^{5/2)}