What is the tangent of f(x)=-5-2x^2,(-3,-23) ?

The tangent of f(x)=-5-2x^2,(-3,-23) is y=12x+13

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tangent of f(x)=-5-2x^2,(-3,-23)

tangent of

f (x) = - 5 - 2 x^{2}, (- 3, - 23)

y = 12 x + 13

Solution steps

Find the slope of

f (x) = - 5 - 2 x^{2} : \frac{df ( x )}{d x} = - 4 x

Compute the slope of

f (x) = - 5 - 2 x^{2}

(- 3, - 23) : m = 12

Find the line with slope m=

12

and passing through

(- 3, - 23) : y = 12 x + 13

y = 12 x + 13

y^{^{'}} + e^{x} y = 2 e^{x}

\frac{d y}{d x} + y = x y e^{- 4 x}

\int sin (θ) e^{c o s (θ)} d θ

\int_{1}^{3} x d x

\int e^{2 x} cos (4 x) d x

What is the tangent of f(x)=-5-2x^2,(-3,-23) ?
The tangent of f(x)=-5-2x^2,(-3,-23) is y=12x+13