What is the integral of 2x^{1/3} ?

The integral of 2x^{1/3} is 3/2 x^{4/3}+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral of 2x^{1/3}

\int 2 x^{\frac{1}{3}} d x

\frac{3}{2} x^{\frac{4}{3}} + C

Solution steps

\int 2 x^{\frac{1}{3}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int x^{\frac{1}{3}} d x

Apply the Power Rule

: \frac{3}{4} x^{\frac{4}{3}}

= 2 \cdot \frac{3}{4} x^{\frac{4}{3}}

Simplify

2 \cdot \frac{3}{4} x^{\frac{4}{3}} : \frac{3}{2} x^{\frac{4}{3}}

= \frac{3}{2} x^{\frac{4}{3}}

Add a constant to the solution

= \frac{3}{2} x^{\frac{4}{3}} + C

x \to \infty lim (cos (x))

y^{^{''}} + 12 y^{^{'}} + 36 y = e^{- 5 x} (x^{2} - 2 x + 3)

\frac{e ^{x - 2}}{x - 1}

n = 0 \sum \infty \frac{1}{( 2 n ) !}