What is area y=\sqrt[3]{2x},y= 1/8 x^2 ?

The answer to area y=\sqrt[3]{2x},y= 1/8 x^2 is 10/3

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area y=\sqrt[3]{2x},y= 1/8 x^2

area

\frac{10}{3}

Decimal Notation

3.33333 \dots

Solution steps

Apply the area formula:

Solve

The area is:

= \frac{10}{3}

\frac{d}{d x} (arctan (x^{2} + 2 x) + C)

\int \frac{x}{1 + 5 x ^{2}} d x

y = 3 x^{2} + \frac{1}{x}

\int x^{e} d x

\int \frac{2}{e ^{x} 11 + e ^{2 x}} d x

What is area y=\sqrt[3]{2x},y= 1/8 x^2 ?
The answer to area y=\sqrt[3]{2x},y= 1/8 x^2 is 10/3