What is the derivative of 3(9x-4^4) ?

The derivative of 3(9x-4^4) is 108(9x-4)^3

What is the first derivative of 3(9x-4^4) ?

The first derivative of 3(9x-4^4) is 108(9x-4)^3

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\frac{d}{d x} (3 (9 x - 4)^{4})

108 (9 x - 4)^{3}

Solution steps

\frac{d}{d x} (3 (9 x - 4)^{4})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d x} ((9 x - 4)^{4})

Apply the chain rule:

4 (9 x - 4)^{3} \frac{d}{d x} (9 x - 4)

= 4 (9 x - 4)^{3} \frac{d}{d x} (9 x - 4)

\frac{d}{d x} (9 x - 4) = 9

= 3 \cdot 4 (9 x - 4)^{3} \cdot 9

Simplify

= 108 (9 x - 4)^{3}

\int \frac{x}{( x - 1 ) ^{3}} d x

y^{^{'}} + 2 \cdot y = t

\frac{d}{d x} (ln (x + 4 + x^{2}))

\frac{\partial}{\partial x} (e^{x} ln (x y))

2 x^{3} - 3 x^{2} - 12 + 8

What is the derivative of 3(9x-4^4) ?
The derivative of 3(9x-4^4) is 108(9x-4)^3
What is the first derivative of 3(9x-4^4) ?
The first derivative of 3(9x-4^4) is 108(9x-4)^3