What is the derivative of 2x^3-3x^2-12+8 ?

The derivative of 2x^3-3x^2-12+8 is 6x^2-6x

What is the first derivative of 2x^3-3x^2-12+8 ?

The first derivative of 2x^3-3x^2-12+8 is 6x^2-6x

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derivative of

2 x^{3} - 3 x^{2} - 12 + 8

6 x^{2} - 6 x

Solution steps

\frac{d}{d x} (2 x^{3} - 3 x^{2} - 12 + 8)

Simplify

2 x^{3} - 3 x^{2} - 12 + 8 : 2 x^{3} - 3 x^{2} - 4

= \frac{d}{d x} (2 x^{3} - 3 x^{2} - 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (4)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (4) = 0

= 6 x^{2} - 6 x - 0

Simplify

= 6 x^{2} - 6 x

n = 1 \sum \infty 7^{n} x^{n - 1}

y^{^{''}} + 6 y^{^{'}} + 8 y = cos (3 t), y (0) = - 2, y^{^{'}} (0) = 1

\int_{6}^{8} \frac{86}{( x - 6 ) ^{3}} d x

\frac{\partial}{\partial x} (2 x^{4} y^{2} + 3 x^{2} y^{4})

\int \frac{cos ( e ^{- x} )}{e ^{2 x}} d x

What is the derivative of 2x^3-3x^2-12+8 ?
The derivative of 2x^3-3x^2-12+8 is 6x^2-6x
What is the first derivative of 2x^3-3x^2-12+8 ?
The first derivative of 2x^3-3x^2-12+8 is 6x^2-6x