What is the integral from 1 to 0 of x^2 ?

The integral from 1 to 0 of x^2 is -1/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 0 of x^2

\int_{1}^{0} x^{2} d x

- \frac{1}{3}

Decimal Notation

- 0.33333 \dots

Solution steps

\int_{1}^{0} x^{2} d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{0}^{1} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{0}^{1}

= - [\frac{x ^{3}}{3}]_{0}^{1}

Compute the boundaries:

\frac{1}{3}

= - \frac{1}{3}

\frac{d}{d x} (sin^{3} (2 x) + x^{2})

y^{^{''}} - 4 y + 3 y = 0

\int \frac{5 x ^{2} + 2 x}{x ^{2} - 5 x - 6} d x

\frac{d y}{d x} = \frac{y ( ln ( y ) - ln ( x ) + 1 )}{x}

2 x, x^{2} - 3

What is the integral from 1 to 0 of x^2 ?
The integral from 1 to 0 of x^2 is -1/3