What is implicit y^2=x^2-xc ?

The answer to implicit y^2=x^2-xc is (dy)/(dx)=(2x-c)/(2y)

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implicit y^2=x^2-xc

implicit derivative

y^{2} = x^{2} - x c

\frac{d y}{d x} = \frac{2 x - c}{2 y}

Solution steps

y^{2} = x^{2} - x c

Treat

y

y (x)

Differentiate both sides:

2 y \frac{d y}{d x} = 2 x - c

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{2 x - c}{2 y}

\frac{d y}{d x} = \frac{2 x - c}{2 y}

\frac{d}{d x} (\frac{5 x}{1 + x ^{2}})

x \to 1 lim (\frac{x}{4 x - 1})

f (x) = x^{2}, (- 4, 15)

(8 x^{2} - 16 x + 16) e^{x}

x \to 1 lim (ln (e^{x} - 1))

What is implicit y^2=x^2-xc ?
The answer to implicit y^2=x^2-xc is (dy)/(dx)=(2x-c)/(2y)