What is implicit (dy)/(dx),y=arcsin(2x+1) ?

The answer to implicit (dy)/(dx),y=arcsin(2x+1) is (dy)/(dx)= 1/(sqrt(-x(x+1)))

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implicit (dy)/(dx),y=arcsin(2x+1)

implicit derivative

\frac{d y}{d x}, y = arcsin (2 x + 1)

\frac{d y}{d x} = \frac{1}{- x ( x + 1 )}

Solution steps

y = arcsin (2 x + 1)

Treat

y

y (x)

Differentiate both sides:

\frac{d y}{d x} = \frac{1}{- x ( x + 1 )}

Isolate

\frac{d y}{d x} : \frac{d y}{d x} = \frac{1}{- x ( x + 1 )}

\frac{d y}{d x} = \frac{1}{- x ( x + 1 )}

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What is implicit (dy)/(dx),y=arcsin(2x+1) ?
The answer to implicit (dy)/(dx),y=arcsin(2x+1) is (dy)/(dx)= 1/(sqrt(-x(x+1)))