What is the d/(dt)(cos(5t)) ?

The d/(dt)(cos(5t)) is -sin(5t)*5

What is the first d/(dt)(cos(5t)) ?

The first d/(dt)(cos(5t)) is -sin(5t)*5

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\frac{d}{d t} (cos (5 t))

- sin (5 t) \cdot 5

Solution steps

\frac{d}{d t} (cos (5 t))

Apply the chain rule:

- sin (5 t) \frac{d}{d t} (5 t)

= - sin (5 t) \frac{d}{d t} (5 t)

\frac{d}{d t} (5 t) = 5

= - sin (5 t) \cdot 5

\int_{- 2}^{2} x^{3} - 4 x d x

\int \frac{( 1 - x ^{2} ) ^{\frac{1}{2}}}{x ^{4}} d x

\int 4 r - r^{2} sin (θ) d r

- 6 x^{2} y + y^{^{'}} = - 10 x^{2}

\frac{1}{s ( s ^{2} + 2 s + 2 )}